Q:

A city's population is represented by the function P=25,000(1.0095)t P=25,000(1.0095)t , where t is time in years.How could the function be rewritten to help identify the daily growth rate of the population? What is the approximate daily growth rate?Function P= 25,000 (1.00095 ^1/365t) ^365tFunctions:P = 25,000 (1.0095 ^1/365) ^365tP = 25,000 (1 + 0.0095) ^t/365P = 25,000 (1 + 0.0095 ^1/365) ^365tDaily Growth Rates:0.003%0.95%0.0012%

Accepted Solution

A:
To convert the function representing the yearly growth of population , to the function representing the daily growth of population we divide the rate of increase by 365 , as there are 365 days in a year.Now the given function is [tex] P=25,000(1.0095)^t [/tex]which can be written as [tex] P=25,000(1+0.0095)^t [/tex]It means the yearly rate of increase is 0.0095, we divide it by 365So The daily growth is given by[tex] P=25,000(1+\frac{0.0095}{365})^{365t} [/tex]And the approximate daily growth rate is[tex] \frac{0.0095}{365} *100 [/tex]= 0.003%