Q:

A sample of 25 cereal boxes of Granola Crunch, a generic brand of cereal, yields a mean (X¯) weight of 1.02 pounds. The goal is to construct a 95% confidence interval for the mean weight (µ) of all cereal boxes of Granola Crunch. Assume that the weight of cereal boxes is normally distributed with a population standard deviation (σ) of 0.03 pounds.

Accepted Solution

A:
Answer:1.01 < µ < 1.03Step-by-step explanation:We want to construct a 95% confidence interval.  Our sample size is 25, so we use a t-value.  The degrees of freedom are 24 (always one less than the sample size).  The t-value we get is:  2.064We have:x = 1.02σ = 0.03See the attached photo for the construction of the confidence interval...