Find the area of the shaded regions below. Give your answer as a completely simplified exact value in terms of π (no approximations). PLSS Solve Both Thanks

Answer:Part 1) The area of the shaded region is [tex]576\ cm^{2}[/tex]Part 2) The area of the shaded region is [tex]A=(18+4.5\pi)\ cm^{2}[/tex]Step-by-step explanation:Part 1) Figure N 1I assume that the figure ABCD is a squarewe know thatThe area of the shaded region is equal to the area of the square ABCD minus the area of semicircle BC plus the area of semicircle ADthereforeThe area of the shaded region is equal to the area of the square ABCDThe area of the square is [tex]A=24^{2}=576\ cm^{2}[/tex]Part 2) Figure N 2I assume that the triangle ABC is a right isosceles trianglesoAB=BCAB ⊥ BCThe area of the shaded region is equal to the area of triangle plus the area of semicircleA) Find the area of the triangle ABCThe area of triangle is[tex]A=\frac{1}{2}(AB)(BC)[/tex]substitute[tex]A=\frac{1}{2}(6)(6)[/tex][tex]A=18\ cm^{2}[/tex]B) Find the area of semicircleThe area of semicircle is equal to[tex]A=\frac{1}{2}\pi r^{2}[/tex]we have[tex]r=BC/2=6/2=3\ cm[/tex] -----> the radius is half the diametersubstitute[tex]A=\frac{1}{2}\pi (3)^{2}[/tex][tex]A=4.5\pi\ cm^{2}[/tex]thereforeThe area of the figure is equal to[tex]A=(18+4.5\pi)\ cm^{2}[/tex]